Panjang sebatang aluminium pada suhu 20° adalah 1 meter. Berapa mm kah panjangnya pada suhu 120°c jika diketahui koefisien muai panjang aluminium 0,000024/°?
Asruul
Diketahui = Lo = 1 m Δt = 120 - 20 = 100'C α = 0,000024/'C Ditanya = Lt..? Jawab = Lt = Lo (1 + α x Δt) = 1 (1 + 0,000024 x 100) = 1 (1 + 0,0024) = 1 x 1,0024 = 1,0024 m = 100.24 cm = 1002.4 mm
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RahyudaLt = Lo (1 + α x Δt) = 1 (1 + 0,000024 x 100) = 1 (1 + 0,0024) = 1 x 1,0024 = 1,0024 m = 100.24 cm = 1002.4 mm
Δt = 120 - 20 = 100'C
α = 0,000024/'C
Ditanya = Lt..?
Jawab = Lt = Lo (1 + α x Δt)
= 1 (1 + 0,000024 x 100)
= 1 (1 + 0,0024)
= 1 x 1,0024
= 1,0024 m
= 100.24 cm
= 1002.4 mm
= 1 (1 + 0,000024 x 100)
= 1 (1 + 0,0024)
= 1 x 1,0024
= 1,0024 m
= 100.24 cm
= 1002.4 mm