Sebuah belahan bola padat memiliki luas permukaan 4.158 cmkuadrat.dengan pi=22/7.maka volume belahan bola tsb adalah...
liwonsubagyo
L.p .½ bola = 1/2 x 4 x 22/7 x r²............. 4.158. = 1/2 x 4 x 22/7 x r²............. 4.158 x 2 = 88/7 x r².......... 8.316. = 88/7 x r²............ r² = √ 8.316 : 88/7.......... = √ 8.316 x 7/88........ = √ 661,5....... = 25,72...... V = 1/2 x 4/3 x 22/7 x 25,72 x 25,72 x 25,72........... =;35.648,91cm³
0 votes
Thanks 1