Volume tangki (v)
= 88 liter
= 88 dm³
= 88.000 cm³
kedalaman air (t)
= 70 cm
phi (π)
[tex] = \frac{22}{7} [/tex]
Jari-jari (r)
v = π × r² × t
[tex]88.000 = \frac{22}{7} \times {r}^{2} \times 70[/tex]
[tex]88.000 \times \frac{7}{22} = {r}^{2} \times 70[/tex]
[tex]44.000 \times 7 = {r}^{2} \times 70[/tex]
[tex] \frac{44.000 \times 7}{70} = {r}^{2} [/tex]
[tex] {r}^{2} = \frac{44.000}{10} [/tex]
[tex] {r}^{2} = 4.400[/tex]
[tex]r = \sqrt{4.400} [/tex]
[tex]r = 66,332[/tex]
Jadi, jari-jari kerucut tersebut adalah 66,332 cm
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Jawaban:
Volume tangki (v)
= 88 liter
= 88 dm³
= 88.000 cm³
kedalaman air (t)
= 70 cm
phi (π)
[tex] = \frac{22}{7} [/tex]
Jari-jari (r)
v = π × r² × t
[tex]88.000 = \frac{22}{7} \times {r}^{2} \times 70[/tex]
[tex]88.000 \times \frac{7}{22} = {r}^{2} \times 70[/tex]
[tex]44.000 \times 7 = {r}^{2} \times 70[/tex]
[tex] \frac{44.000 \times 7}{70} = {r}^{2} [/tex]
[tex] {r}^{2} = \frac{44.000}{10} [/tex]
[tex] {r}^{2} = 4.400[/tex]
[tex]r = \sqrt{4.400} [/tex]
[tex]r = 66,332[/tex]
Jadi, jari-jari kerucut tersebut adalah 66,332 cm