Question

jika diameter lingkara 42 cm, π = 22/7.
Hitunglah
a. Luas Juring XOY
b. Panjang Busur kecil XY​

Answer 1

Jawab:
a. Juring ≈ 519,75 cm²
b. Busur ≈ 49,5 cm

Penjelasan dengan langkah-langkah:

Diketahui:
Sudut (θ) = 135°
Diameter (d) = 42 cm
π ≈ ²²/₇

Ditanya: a. Luas juring
Juring = θ×¹/₃₆₀×¹/₄×π×d²
Juring ≈ 135°×¹/₃₆₀×¹/₄ײ²/₇×42²
Juring ≈ 135°×¹/₃₆₀×¹/₄×22×6×42
Juring ≈ 135°×¹/₃₆₀ײ¹/₂×22×6
Juring ≈ 135°×¹/₃₆₀×21×11×6
Juring ≈ 135°×¹/₃₆₀×21×11×6
Juring ≈ ³/₈×21×11×6
Juring ≈ ¹⁸/₈×21×11
Juring ≈ ¹⁸/₈×231
Juring ≈ ⁴¹⁵⁸/₈
Juring ≈ 519,75 cm²

Ditanya: b. Busur
Busur = θ×¹/₃₆₀×π×d
Busur ≈ 135°×¹/₃₆₀ײ²/₇×42
Busur ≈ ³/₈ײ²/₇×42
Busur ≈ ³/₈×22×6
Busur ≈ ³/₈×132
Busur ≈ ³⁹⁶/₈
Busur ≈ 49,5 cm

(xcvi)