Rownanie pierwszego stopnia .
zad.1. Rozwiaz rownania;
2(x+3)-3(x+1)=x-13
5-3x-13/7=3x
3x(x-2)+5=3+x(2+3x)
zad.2.Wyznacz ze wzoru wskazana zmienna:
ax=2b-1 b
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2(x+3)-3(x+1)=x-13
2x+6-3x-3-x+13=0
-2x+10=0
2x=10
x=5
5-3x-13/7=3x //*7
35-31x-13-21x=0
-52x+22=0
52x=22
x=11/26
3x(x-2) +5 = 3+x(2+3x)
3x²-6x+5=3+2x+6x²
3x²-6x²-6x-2x+5-3=0
-3x²-8x+2=0
Δ=64-4*(-3)*2=64+24=88
√Δ=2√22
x₁=(8-2√22)/(-6)=(√22-4)/3
x₂=(8+2√22)/)-6)=-(4+√22)/3
ax=2b-1
2b=ax-1
b=(ax-1)/2