Titik Berat
▶ Bangun Datar
I = Persegi panjang ; II : Segitiga
y₁ = ½ (4) = 2
A₁ = 16 × 4
A₁ = 64 satuan luas
y₂ = 4 + ⅓ (t)
y₂ = 4 + ⅓ (6)
y₂ = 6
A₂ = ½ × 16 × 6
A₂ = 48 satuan luas
y₀ = __ ?
koordinat titik berat pada sumbu y
y₀ = (y₁ A₁ + y₂ A₂) / (A₁ + A₂)
y₀ = (2 × 64 + 6 × 48) / (64 + 48)
y₀ = 416/112
y₀ = 26/7 ✔
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Titik Berat
▶ Bangun Datar
I = Persegi panjang ; II : Segitiga
y₁ = ½ (4) = 2
A₁ = 16 × 4
A₁ = 64 satuan luas
y₂ = 4 + ⅓ (t)
y₂ = 4 + ⅓ (6)
y₂ = 6
A₂ = ½ × 16 × 6
A₂ = 48 satuan luas
y₀ = __ ?
koordinat titik berat pada sumbu y
y₀ = (y₁ A₁ + y₂ A₂) / (A₁ + A₂)
y₀ = (2 × 64 + 6 × 48) / (64 + 48)
y₀ = 416/112
y₀ = 26/7 ✔