Bentuk akar
(x + y √2) (3 -√2) = - √2
(x + y√2) = - √2 / (3 - √2)
= { - √2 (3 + √2)}/ { (3 - √2)(3 + √2)}
= (- 3√2 - 2 ) / (9 - 2)
= - ( 2 + 3√2) /(7)
= - 1/7 (2 + 3√2)
(x + y√2)= ( - 2/7 - 3/7 √2)
x = -2/7
y = - 3/7
x - y = (- 2/7) - ( - (-3/7) = - 2/7 + 3/7
x - y = 1/7
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Verified answer
Bentuk akar
(x + y √2) (3 -√2) = - √2
(x + y√2) = - √2 / (3 - √2)
= { - √2 (3 + √2)}/ { (3 - √2)(3 + √2)}
= (- 3√2 - 2 ) / (9 - 2)
= - ( 2 + 3√2) /(7)
= - 1/7 (2 + 3√2)
(x + y√2)= ( - 2/7 - 3/7 √2)
x = -2/7
y = - 3/7
x - y = (- 2/7) - ( - (-3/7) = - 2/7 + 3/7
x - y = 1/7