Zapisz w jak najprostrzej postaci. a) 3x - 2xy + 5x = b) (5x - 7y) - (3y - 7x) = c) -(a-2b)

October 2018 1 19 Report

Zapisz w jak najprostrzej postaci.
a) 3x - 2xy + 5x =
b) (5x - 7y) - (3y - 7x) =
c) -(a-2b) - 2(y-3x) =
d) 3(x-2y) - 2(y-3x) =
Zapisz w jak najprostrzej postaci :
a) (2x+y) (x-2y) - x (x+y) =
b) (3a-2b) (a-b) +2 (a-b) (a-2b) =
c) (4k+1) (2k-1) - (k-1) (k-3) =
Uzupełnij :
√ =11
√ =13
√ =1/4
√ =0,1
∛ =0,1
∛ =-5
∛ =-2/3
∛ =1 1/3
Uzupełnij:
√36 × √144 =
√9 × √ =21
√ : √25 =2
∛27 × ∛-8 =
∛64 × ∛ =40
∛125 × ∛ =-5
√121 × ∛-27 =

∛216 × √ =36

√196 : ∛ =-7
Zapisz w prostrzej postaci:
8√7 + √7 =
10 + 5√6 - 2√6 =
2√13 - 1 + √13 =
3∛10 - ∛10 =
-∛5 + ∛-5 =
3∛9 - ∛-9 =
Zapisz w jak najprostrzej postaci:
√7² + √6 - ( √6)² =
∛12³ - (√17)² - √5 =
3√5² + 2√5 - 2∛(-5)³ =
-∛5³ - ∛7 - ∛-7 =
Zapisz w postaci jednej potęgi:
(6³)⁴ × (6²)³ =
(7²)⁵ × (7⁵)² =
(( 1/3)³)³ × (( 1/3)²)² =
(5⁸)⁷ : (5⁶)⁸ =
(0,6⁴)⁵ : (0,6²)¹⁰ =
(( 5/7)³)⁸ : (( 5/7²)¹⁰ =

kamhub14

a) 3x - 2xy + 5x = 8x-2xy
b) (5x - 7y) - (3y - 7x) = 5x-7y-3y+7x=12x-10y
c) -(a-2b) - 2(y-3x) = -a+2b-2y+6x
d) 3(x-2y) - 2(y-3x) = 3x-6y-2y+6x=9x-8y

$a) (2x+y) (x-2y) - x (x+y) =2x^2-4xy+xy-2y^2-x^2-xy\\\ =x^2-4xy-2y^2 \\\ b) (3a-2b) (a-b) +2 (a-b) (a-2b) = 3a^2-3ab-2ab+2b^2+\\\ 2a^2-4ab-2ab+4b^2=5a^2-11ab+6b^2\\\ c) (4k+1) (2k-1) - (k-1) (k-3) = 8k^2-4k+2k-1-k^2\\\ +3k+k-3=7k^2+2k-4$

$\sqrt{121}=11\\\ \sqrt{169}=13\\\ \sqrt{\frac{1}{16}}=\frac{1}{4}\\\ \sqrt{0.01}}=0,1\\\ \sqrt[3]{0.001}=0,1\\\ \sqrt[3]{-125}=-5\\\ \sqrt[3]{-\frac{8}{27}}=-\frac{2}{3}\\\ \sqrt[3]{\frac{64}{27}}=1\frac{1}{3}$

$\sqrt{36} * \sqrt{144} =6*12=72 \\\ \sqrt{9}*\sqrt{49} =21(bo:3*7=21)\\\ \sqrt{100}:\sqrt{25} =2(bo:10:5=2)\\\ \sqrt[3]{27}*\sqrt[3]{-8} =3*(-2)=-6\\\ \sqrt[3]{64}*\sqrt[3]{1000} =40(bo:4*10=40)\\\ \sqrt[3]{125}* \sqrt[3]{-1} =-5(bo:5*(-1)=-5)\\\ \sqrt{121}*\sqrt[3]{-27} =11*(-3)=-33\\\ \sqrt[3]{216}*\sqrt{36} =36(bo:6*6=36)\\\ \sqrt{196} : \sqrt[3]{-8}=-7(bo:14:(-20)=-7)$

$8\sqrt{7} + \sqrt{7} =9\sqrt{7}\\\ 10 + 5\sqrt{6} - 2\sqrt{6} =10+3\sqrt{6}\\\ 2\sqrt{13} - 1 + \sqrt{13} =3\sqrt{13}-1\\\ 3\sqrt[3]{10} - \sqrt[3]{10} =2\sqrt[3]{10}\\\ \sqrt[3]{-5} + \sqrt[3]{-5} =2\sqrt[3]{-5}\\\ 3\sqrt[3]{9} - \sqrt[3]{9} =2\sqrt[3]{9}$

$\sqrt{7^2} + \sqrt{6} - ( \sqrt{6})^2 =7+\sqrt{6}-6=1+\sqrt{6}\\\ \sqrt[3]{12^3} - (\sqrt{17})^2 - \sqrt{5} =12-17-\sqrt{5}=-5-\sqrt{5}\\\ 3\sqrt{5^2} + 2\sqrt{5} - 2\sqrt[3]{(-5)^3} =3*5+2\sqrt{2}-2*(-5)=25+2\sqrt{2}\\\ -\sqrt[3]{5^3} - \sqrt[3]{7} - \sqrt[3]{7} = -5-2\sqrt[3]{7}$

$(6^3)^4 *(6^2)^3 =6^1^2*6^6=6^1^8\\\ \\\ (7^2)^5* (7^5)^2 =7^1^0*7^1^0=7^2^0\\\ \\\ ((\frac{1}{3})^3)^3 *((\frac{1}{3})^2)^2 =(\frac{1}{3})^9*(\frac{1}{3})^4=(\frac{1}{3})^1^3\\\ \\\ (5^8)^7 : (5^6)^8 =5^5^6:5^4^8=5^8\\\ \\\ (0,6^4)^5 : (0,6^2)^1^0 =(0.6)^2^0:(0.6)^2^0=(0.6)^0=1 \\\ \\\ ((\frac{5}{7})^3)^8 : ((\frac{5}{7})^2)^1^0=(\frac{5}{7})^2^4:(\frac{5}{7})^2^0=(\frac{5}{7})^4$