Zad. 1 Dany jest kąt ostry (alfa).Wiedząc że : a).cos (alfa)=1/3 wyznacz sin(alfa), b).tg(alfa)=2/7 wyznacz ctg(alfa).
a)
1=cos²α+sin²α
sinα=√1-1/9=2√2/3
b)
tgα=sinα/cosα=2/7
ctgα=cosα/sinα
ctgα=7/2
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a)
1=cos²α+sin²α
sinα=√1-1/9=2√2/3
b)
tgα=sinα/cosα=2/7
ctgα=cosα/sinα
ctgα=7/2