Di ketahui luas selimut tabung 440 cm dan tinggi tabung 20 jika phi 22/7 maka volume tabung adalah
5dregensleyer
luas selimut = 440 2 x π x r x t = 440 2 x 22/7 x r x t = 440 44/7 x r x 20 = 440 880/7 x r = 440 r = 440 x 7/880 r = 3,5 cm volum = π x r² x t = 22/7 x 3,5 x 3,5 x 20 = 22 x 1,5 x 3,5 x 20 = 6930 cm ³
jawabannya 6930 cm³
0 votes Thanks 0
AnandaHafidhR
L. selimut tabung = πdt 440 = 22/7 x d x 20 d = 440 x 7/22 : 20 d = 20 x 7 : 20 d = 140 : 20 d = 7 cm r = 3,5 cm
v tabung = πr²t = 22/7 x 3,5 x 3,5 x 20 = 22 x 0,5 x 70 = 11 x 70 = 770 cm³
2 x π x r x t = 440
2 x 22/7 x r x t = 440
44/7 x r x 20 = 440
880/7 x r = 440
r = 440 x 7/880
r = 3,5 cm
volum = π x r² x t
= 22/7 x 3,5 x 3,5 x 20
= 22 x 1,5 x 3,5 x 20
= 6930 cm ³
jawabannya 6930 cm³
440 = 22/7 x d x 20
d = 440 x 7/22 : 20
d = 20 x 7 : 20
d = 140 : 20
d = 7 cm
r = 3,5 cm
v tabung = πr²t
= 22/7 x 3,5 x 3,5 x 20
= 22 x 0,5 x 70
= 11 x 70
= 770 cm³