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|a| = 4
|b| = 14
cos α = 3/7
a(a+b) = a.a+ a.b
menentukan sudut dalam vektor :
cos α = a.b / |a| |b|
a.b = |a| |b| cos α
a.a = |a|²
a(a+b) = |a|² + |a| |b| cos α
a(a+b) = 4² + 4 . 14 . 3/7
a(a+b) = 16 + 56 . 3/7
a(a+b) = 16 + 24
a(a+b) = 40
Jawaban : C.40
Jadikan yang terbaik ya^_^…
Mapel : Matematika
Kelas : 10
Material : Vektor
Kode Kategorisasi : 10.2
Link Materi Vektor :
brainly.co.id/tugas/20285417
brainly.co.id/tugas/10788175