October 2018 1 41 Report

wyznacz x, jeśli:

(x+2) · [log₃3/7 + log₃21]=log₄4^x-1 (to jest 4 do potęgi x-1)

wyszło mi coś takiego: 2x+4=log₄4^x-1 i dalej nie wiem co z tym zrobić


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