wyznacz x, jeśli:
(x+2) · [log₃3/7 + log₃21]=log₄4^x-1 (to jest 4 do potęgi x-1)
wyszło mi coś takiego: 2x+4=log₄4^x-1 i dalej nie wiem co z tym zrobić
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(x+2) · [log₃3/7 + log₃21]=log₄4^x-1
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(x+2) · [log₃(3/7·21)] = log₄4^x-1
(x+2) · log₃9 = x-1
(x+2) · log₃3² = x-1
(x+2) · 2 = x-1
2x+4 = x-1
x = -5
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Wykorzystane wzory:
(log₄4^x-1 = x-1)