Question

Prize 10 Poin

Luas sebuah bbp (Belahan Bola Padat) 4.158cm². jika pendekatan nilai π= 22/7. hitunglah volume bbp (Belahan benda padat)

(pake cara)

Answer 1

Verified answer

Luas bbp = 3 πr²
4158 = 3×22/7 ×r²
4158 = 66/7 × r²
4158 ÷ 66/7 = r²
4158 × 7/66 = r²
441 = r²
r = akar kuadrat dari 441
r = 21 cm

volume bbp = 1/2 × 4/3 × π ×r^3
= 1/2×4/3×22/7×21^3
=88/42×9261
= 19404 cm^3

Answer 2

Verified answer

Lbbp = 4158 cm^2
phi = 22/7
Lbbp = (1/2 × 4 × phi × r^2) + (phi × r^2)
4158 = (1/2 × 4 × 22/7 × r^2) + (22/7 × r^2)
4158 = (44/7 × r^2) + (22/7 × r^2)
4158 = r^2 × (44/7 + 22/7)
4158 = r^2 × 66/7
r^2 = 4158/(66/7)
r^2 = 4158 × 7/66
r^2 = 441
r = V441
r = 21 cm
Vbbp = 1/2 × 4/3 × phi × r^3
Vbbp = 1/2 × 4/3 × 22/7 × 21^3
Vbbp = 1/2 × 4/3 × 22/7 × 9261
Vbbp = 19404 cm^3
Jadi volume belahan bola padat adalah 19404 cm^3