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t = 12
a. Ls = 2πrt
528 = 2 x 22/7 x r x 12
r = 7
b . Lp = 2πr (r + t) = 2 x 22/7 x 7 ( 7 + 12) = 836
Luas selimut = 528 cm²
t = 12 cm
Ditanya : a) r ?
b) Luas permukaan tabung ?
Dijawab :
Luas selimut = 2πrt
528 = 2 . 22/7 . r . 12
528 = 528/7 r
r = 528 : 528/7
r = 7 cm
Maka,
Luas permukaan tabung = 2Luas alas +Luas selimut
= 2πr² +528
= 2 . 22/7 . 7 . 7 +528
= 308 +528
= 836 cm²
Jadi, luas permukaan tabung adalah 836 cm².