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luas selimut = 550 cm^2
garis pelukis = 25
ditanya
a. r kerucut
b. L alas
c. L permukaan
jawab;
a. r kerucut = keliling alas / (2 x )
keliling alas = 2 x luas selimut /garis pelukis = 2 x 550 / 25 = 44
r kerucut = 44 / (2 x 22/7) = 7.
Jadi, jari-jari kerucut = 7 cm
b. luas alas = x (r kerucut)^2 = 22/7 x 7^2 = 144
Jadi Luas alas kerucut 144 cm^2
c. Luas Permukaan = Luas alas + luas selimut = 144 + 550 = 694
Jadi, Luas permukaan kerucut 694 cm^2
Luas selimut = π r s
maka
r = luas selimut x 1
s π
= 550 x 7
25 22
= 7 cm
Luas alas = π r²
= x 49 = 154 cm²
Luas permukaan = π r ( r + s )
= x 7 ( 7 + 25)
= 22 x 32
= 704 cm³
moga membantu ... ^_^