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f(-3)⇒ a(-3) + b = - 15
f( 3)⇒ a (-3) + B = 9
PERSAMAAN
-3a + b = -15
3a + b = 9 _ eliminasikan
-6a = - 24
a = -24/-6
a = 4
subtitusikan
3a + b = 9
b = 9 - 3a
b = 9 - 3(4)
b = 9 - 12
b = -3
maka hasil dari
f(-2) + f (2) = 3x - 3 + 3x - 3
= 3(-2) -3 + 3(2) - 3
= -6 - 3 + 6 - 3
= - 6
jawabnnya adalah -6
f(-3) = -15
f(3) = 9
Dengan:
f(x) = ax + b
Dengan substitusi akan memberikan:
-15 = a(-3) + b, alias -3a + b = -15 [Persamaan 1]
9 = a(3) + b, alias 3a + b = 9 [Persamaan 2]
Eliminasikan untuk a, dan b.
-3a + b = -15
3a + b = 9 -
-6a = -24
Didapat, a = 4
Substitusikan a untuk b,
3(4) + b = 9
12 + b = 9
Akan didapat b = -3
Sehingga:
f(x) = ax + b
f(x) = 4x - 3
Dengan demikian:
f(-2) + f(2)
= [4(-2) - 3] + [4(2) - 3]
= [-8 - 3] + [8 - 3]
= -11 + 5
= -6