pelukis = √7²+24² = √49+576 = √625 = 25 cm Luas selimut = 25 x 22/7 x 7 = 550 cm2 luas sisi kerucut = 154 + 550 = 704 cm2 volume kerucut = 1/3 x 154 x 24 = 1232 cm3
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5dregensleyer
Luas alas = 154 π x r² = 154 22/7 x r² = 154 r² = 154 x 7/22 r² = 49 r = √49 r = 7 cm mencari sisi miring s² = 24² + 7² = √ 576 + 49 = √ 625 = 25 cm
jawaban soal A Ls = π x r x s = 22/7 x 7 x 25 = 550 cm²
jawaban soal B luas sisi Lp = La + Ls = 550 + 154 = 704 cm²
jawaban soal C Volum = 1/3 x La x t = 1/3 x 154 x 24 = 154 x 8 = 1232 cm³
7 x 7 = r^2
7 cm = r
pelukis = √7²+24² = √49+576 = √625 = 25 cm
Luas selimut = 25 x 22/7 x 7 = 550 cm2
luas sisi kerucut = 154 + 550 = 704 cm2
volume kerucut = 1/3 x 154 x 24 = 1232 cm3
π x r² = 154
22/7 x r² = 154
r² = 154 x 7/22
r² = 49
r = √49
r = 7 cm
mencari sisi miring
s² = 24² + 7²
= √ 576 + 49
= √ 625
= 25 cm
jawaban soal A
Ls = π x r x s
= 22/7 x 7 x 25
= 550 cm²
jawaban soal B
luas sisi
Lp = La + Ls
= 550 + 154
= 704 cm²
jawaban soal C
Volum = 1/3 x La x t
= 1/3 x 154 x 24
= 154 x 8
= 1232 cm³