Question

pd gambar berikut besar sudut hog=90° dan panjang jari² 21 cm dgn π=22/7. A.luas daerah diarsir (tembereng) ​

Answer 1

Verified answer

Penjelasan dengan langkah-langkah:

Unsur Lingkaran

r = 21 cm

HOG° = 90°

Dit : Luas Tembereng

Jawab :

= Luas juring - Luas segitiga

= (90/360 × 22/7 × 21 × 21) - (½ × sin 90° × 21 × 21)

= (¼ × 22 × 3 × 21) - ( ½ × 1 × 441 )

= (346,5) - (220,5)

= 126 cm²

Answer 2

Bangun Datar

[Lingkaran]

..

[tex]\begin{aligned} L.Tembereng \: {(90^\circ)} &= 1/4 \times r^2 \times (\pi - 2) \\&= 1/4 \times (21~cm)^2 \times (22/7 - 2) \\&= 1/4 \times 441~cm^2 \times (22/7 - 14/7) \\&= 110.25~cm^2 \times 8/7 \\&= \boxed{\bold{\underline{126~cm^2}}} \end{aligned}[/tex]

[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 26 - 05 - 2023}}[/tex]