Penjelasan dengan langkah-langkah:
Unsur Lingkaran
r = 21 cm
HOG° = 90°
Dit : Luas Tembereng
Jawab :
= Luas juring - Luas segitiga
= (90/360 × 22/7 × 21 × 21) - (½ × sin 90° × 21 × 21)
= (¼ × 22 × 3 × 21) - ( ½ × 1 × 441 )
= (346,5) - (220,5)
= 126 cm²
..
[tex]\begin{aligned} L.Tembereng \: {(90^\circ)} &= 1/4 \times r^2 \times (\pi - 2) \\&= 1/4 \times (21~cm)^2 \times (22/7 - 2) \\&= 1/4 \times 441~cm^2 \times (22/7 - 14/7) \\&= 110.25~cm^2 \times 8/7 \\&= \boxed{\bold{\underline{126~cm^2}}} \end{aligned}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 26 - 05 - 2023}}[/tex]
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Verified answer
Penjelasan dengan langkah-langkah:
Unsur Lingkaran
r = 21 cm
HOG° = 90°
Dit : Luas Tembereng
Jawab :
= Luas juring - Luas segitiga
= (90/360 × 22/7 × 21 × 21) - (½ × sin 90° × 21 × 21)
= (¼ × 22 × 3 × 21) - ( ½ × 1 × 441 )
= (346,5) - (220,5)
= 126 cm²
Bangun Datar
[Lingkaran]
..
[tex]\begin{aligned} L.Tembereng \: {(90^\circ)} &= 1/4 \times r^2 \times (\pi - 2) \\&= 1/4 \times (21~cm)^2 \times (22/7 - 2) \\&= 1/4 \times 441~cm^2 \times (22/7 - 14/7) \\&= 110.25~cm^2 \times 8/7 \\&= \boxed{\bold{\underline{126~cm^2}}} \end{aligned}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 26 - 05 - 2023}}[/tex]