Luas selimut kerucut yang berjari 7cm,tinggi 24 cm dan π=22/7 adalah
liliput01
Diket: r = 7cm t = 24cm Dit: Lselimut kerucut....? s = √r² + t² s = √7² + 24² s = √49 + 576 s = √625 s = 25 cm , Lselimut kerucut = πrs = 22/7 x 7 x 25 = 22 x 25 = 550 cm² luas selimut kerucut = 550 cm²
0 votes Thanks 1
fredrikedison
(mencari sisi miring kerucut) s^2 = t^2 + r^2 s^2 = 24^2 + 7^2 s^2 = 576 + 49 s^2 = 625 s = √625 s = 25 cm
(mencari luas selimut kerucut) L selimut = π . r . s = 22/7 . 7 . 25 = 22 . 25 = 550 cm^2
r = 7cm
t = 24cm
Dit: Lselimut kerucut....?
s = √r² + t²
s = √7² + 24²
s = √49 + 576
s = √625
s = 25 cm
,
Lselimut kerucut = πrs
= 22/7 x 7 x 25
= 22 x 25
= 550 cm²
luas selimut kerucut = 550 cm²
s^2 = t^2 + r^2
s^2 = 24^2 + 7^2
s^2 = 576 + 49
s^2 = 625
s = √625
s = 25 cm
(mencari luas selimut kerucut)
L selimut = π . r . s
= 22/7 . 7 . 25
= 22 . 25
= 550 cm^2
Jadi, luas selimut adalah 550 cm^2