October 2018 1 127 Report

a) |3-12-5|| = ?
b) |3√7-5√3 = ?
c) |2-√3|+ |2+√3|= ?
d) |√3 - 5|-|√3 - 1| = ?

e) (3-√2)^2 (wszystko jest pod pierwiastkiem) =

f) (2-√7)^2 pod pierw wszystko =

g) |7-√7|/|7-√7| =

h) |2√5-3|-5|√5-2|+5-3√5|=



More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.