Penjelasan dengan langkah-langkah:
volume kerucut = ¹/₃ x π x r² x t
16.632 = ¹/₃ x ²²/₇ x r² x 36
16.632 = ²²/₇ x 12 x r²
16.632 = ²⁶⁴/₇ x r²
r² = 16.632 x 7 : 264
= 441
r = √441
= 21 cm
Jawaban:
Sebuah wadah berbentuk kerucut dengan volume 16.632cm³ dan tinggi 36 cm. Tentukan jari-jari alas kerucut tersebut! (π = 22/7)
[tex] \sf Volume = \frac{1}{3} \times \pi \times {r}^{2} \times t[/tex]
[tex] \: \: \sf 16.632 = \frac{1}{3} \times \frac{22}{7} \times {r}^{2} \times 36[/tex]
[tex] \: \: \sf 16.632 = \frac{1}{ \cancel{3}} \times \frac{22}{7} \times {r}^{2} \times { \cancel{36}}^{ \: \: 12} [/tex]
[tex] \: \: \sf 16.632 = \frac{22}{7} \times {r}^{2} \times 12[/tex]
[tex] \: \sf {r}^{2} \times 12 = 16.632 : \frac{22}{7} [/tex]
[tex] \: \sf {r}^{2} \times 12 = 16.632 \times \frac{7}{22} [/tex]
[tex] \: \sf {r}^{2} \times 12 = 5.292[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \sf {r}^{2} = \frac{5.292}{12} \\ [/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \sf {r}^{2} = 441[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \sf r = \sqrt{441} [/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \sf r = 21 \: cm[/tex]
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Verified answer
Penjelasan dengan langkah-langkah:
volume kerucut = ¹/₃ x π x r² x t
16.632 = ¹/₃ x ²²/₇ x r² x 36
16.632 = ²²/₇ x 12 x r²
16.632 = ²⁶⁴/₇ x r²
r² = 16.632 x 7 : 264
= 441
r = √441
= 21 cm
Jawaban:
Penyelesaian :
Sebuah wadah berbentuk kerucut dengan volume 16.632cm³ dan tinggi 36 cm. Tentukan jari-jari alas kerucut tersebut! (π = 22/7)
Mencari jari - jari alas
[tex] \sf Volume = \frac{1}{3} \times \pi \times {r}^{2} \times t[/tex]
[tex] \: \: \sf 16.632 = \frac{1}{3} \times \frac{22}{7} \times {r}^{2} \times 36[/tex]
[tex] \: \: \sf 16.632 = \frac{1}{ \cancel{3}} \times \frac{22}{7} \times {r}^{2} \times { \cancel{36}}^{ \: \: 12} [/tex]
[tex] \: \: \sf 16.632 = \frac{22}{7} \times {r}^{2} \times 12[/tex]
[tex] \: \sf {r}^{2} \times 12 = 16.632 : \frac{22}{7} [/tex]
[tex] \: \sf {r}^{2} \times 12 = 16.632 \times \frac{7}{22} [/tex]
[tex] \: \sf {r}^{2} \times 12 = 5.292[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \sf {r}^{2} = \frac{5.292}{12} \\ [/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \sf {r}^{2} = 441[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \sf r = \sqrt{441} [/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \sf r = 21 \: cm[/tex]