1.Oblicz :
(10)⁻⁵
(-4)⁻²
(-2)⁻³
(-⅔)⁻²
(-⅕)⁻³
(-3⅓)⁻⁴
3.Zapisz podane liczby w postaci potęg o wykładniku ujemnym.
(⅓)⁴ , (⅜)³ , 1/7⁵ , 6⁵ , (2¼)⁷
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10⁻⁵=1/10⁵=¹/₁₀₀₀₀₀
(-4)⁻²=1/(-4)²=¹/₁₆
(-2)⁻³=1/(-2)³=-⅛
(-⅔)⁻²=(-³/₂)²=⁹/₄=2¼
(-⅕)⁻³=(-5)³=-125
(-3⅓)⁻⁴=(-¹⁰/₃)⁻⁴=(-³/₁₀)⁴=+⁸¹/₁₀₀₀₀
3)
(⅓)⁴=(3⁻¹)⁴=3⁻⁴
(⅜)³=[(⁸/₃)⁻¹]³=(⁸/₃)⁻³
¹/₇⁵=(7⁻¹)⁵=7⁻⁵
6⁵=[(⅙)⁻¹]⁵=(⅙)⁻⁵
(2¼)⁷=(⁹/₄)⁷=[(⅔)⁻²]⁷=(⅔)⁻¹⁴
np. 1/5 oznacza ułamek
1.
(10) do potęgi -5 = 1/10 do potęgi 5 = 1/100000
(-4) do potęgi -2 = (-1/4) do potęgi 2 = 1/16
(-2) do potęgi -3 = (-1/2) do potęgi 3 = -1/8
(-2/3) do potęgi -2 = (-3/2) do potęgi 2 = 9/4 = 2 i 1/4
(-1/5) do potęgi -3 = (-5/1) do potęgi 3 = -125/1 = -125
(-3 i 1/3) do potęgi -4 = (-10/3) do potęgi -4 = (-3/10) do potęgi 4 = -81/10000
3.
(1/3) do potęgi 4 = 3 do potęgi -4
(3/8) do potęgi 3 = (8/3) do potęgi -3
1/7 do potęgi 5 = 7 do potęgi -5
6 do potęgi 5 = (1/6) do potęgi -5
(2 i 1/4) do potęgi 7 = (9/4) do potęgi 7 = (4/9) do potęgi -7