proszę o rozwiązanie 1 rozszerz ułamek wpisując zamiast x odpowiednia liczbe 1/8=x/120 2 Oblicz a 16/5:0,4 i w mianowniku tylko 3 i za = jest podzielone przez 2 i1/2-1/15 b [{7/8-2/5)-{11/40-2/5}]:(39/20+9/5} c 11/4:1/7-22 i w mianowniku 6-{-5}
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1.
1/8 = 15/120
2.
16/5 : 0,4
__________ : 2i1/2 -1/15 =
3
16/5 * 10/4
= ___________ : 5/2 - 1/15 =
3
4/1 * 2/1
= ___________ : 5/2 -1/15 =
3
= 8/3 *2/5 -1/15= 16/15 - 1/15= 15/15 = 1
b)
[(7/8 -2/5) -(11/40- 2/5)]: (39/20 +9/5) =
= [(35/40 -16/40) - (11/40 -16/40)] : (39/20 + 36/20) =
= [19/40 + 5/40] : 75/20 = 24/40 * 20/75 = 24/2 * 1/75= 24/150 = 12/75
c)
11/4 : 1/7 -22
____________ =
6 -(-5)
11/4 * 7/1 - 22
=____________ =
6 + 5
77/4 - 22
= _________ =
11
19i1/4 - 21i4/4
= _____________ =
11
= -2i3/4 : 11 = -11/4 * 1/11 = -1/4 * 1/1 = -1/4
1/8 = 15/120
16/5 : 0,4 =16/5 * 5/2 = 8
8 : 2 i 1/2 - 1/15 = 8 * 2/5 - 1/15 = 16/5 - 1/5 = 48/15 - 1/15 = 47/15 = 3 i 2/15
[{35/40 - 16/40 ) - {11/40 - 16/40 }] = 19/40 - ( -5/40 ) = 24/40 = 12/20 = 6/10 = 3/5
3/5 : ( 1 i 19/20 + 1 i 4/5 ) = 3/5 : ( 1 i 19/20 + 1 i 16/20 ) = 3/5 : 2 i 35/20 =
= 3/5 : 3 i 15/20 = 3/5 : 3 i 3/4 = 3/5 : 15/4 = 3/5 * 4/15 = 12/75