Zapisz funkcję f(x) = 1/3 x² + 1/6x w postaci iloczynowej. Daje naj :D
f(x) = 1/3 x² + 1/6x
f(x) = 1/3x (x + 1/2) ------ postać iloczynowa
y=⅓x²+⅙x
x(⅓x+⅙)=0
x₁=0 lub ⅓x=-⅙
x=-⅙:⅓
x₂=-½
postac iloczynowa;
f(x)=a(x-x₁)(x-x₂)
f(x)=⅓(x-0)(x+½)
f(x)=⅓x(x+½)
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f(x) = 1/3 x² + 1/6x
f(x) = 1/3x (x + 1/2) ------ postać iloczynowa
y=⅓x²+⅙x
x(⅓x+⅙)=0
x₁=0 lub ⅓x=-⅙
x=-⅙:⅓
x₂=-½
postac iloczynowa;
f(x)=a(x-x₁)(x-x₂)
f(x)=⅓(x-0)(x+½)
f(x)=⅓x(x+½)