rozwiąż równania 1) 3(x+1)=9 2) -(4+x)=8 3) 3/5x + 6x=10 4) 3/4x-2=x+2 5)1/6(x-1)=1 Ten ukonik oznacza ułamek zwykły
1) 3(x+1)=9
3x+3=9
3x=9-3
3x=6 /3
x=2
2) -(4+x)=8
-4-x=8
-x=4+8
-x=12 /-1
x=-12
3) 3/5x + 6x=10
33/5x=10 *5/33
x=50/33
x=1 17/33
4) 3/4x-2=x+2
3/4x-x=2+2
-1/4x=4 *-4
x=-16
5)1/6(x-1)=1
1/6x-1/6=1
1/6x=1/6+1
1/6x=7/6 *6
x=42/6
x=7
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1) 3(x+1)=9
3x+3=9
3x=9-3
3x=6 /3
x=2
2) -(4+x)=8
-4-x=8
-x=4+8
-x=12 /-1
x=-12
3) 3/5x + 6x=10
33/5x=10 *5/33
x=50/33
x=1 17/33
4) 3/4x-2=x+2
3/4x-x=2+2
-1/4x=4 *-4
x=-16
5)1/6(x-1)=1
1/6x-1/6=1
1/6x=1/6+1
1/6x=7/6 *6
x=42/6
x=7