Question

Ułamki zwykłe, Oblicz

a) ( 3 1/2 - 2 2/3 ) do potęgi 2 + 2/3 +7/9
b) ( 2/3 + 1 1/2 ) : ( 4 1/2 )do potęgi 2 - 18 1/6

Dam naj naj

Answer 1

a) ( 3 1/2 - 2 2/3 )^2 + 2/3 +7/9 = (3 3/6 - 2 4/6)^2 + 6/9+7/9 = (5/6)^2 + 6/9+7/9 = 25/36 + 24/36 + 28/36 = 77/36 = 2 5/36
b) ( 2/3 + 1 1/2 ) : ( 4 1/2 )^2 - 18 1/6 = (4/6 + 9/6) : (9/2)^2 - 18 1/6 = 13/6 : 81/4 - 109/6 = 13/6 * 4/81 - 109/6 = 26/243 - 109/6 = 51/486 - 8829/486 = -8778/486 = -4389/243 = - 18 15/243 = - 18 5/81

Answer 2

A) (3i1/2 - 2i2/3)^2 + 2/3 + 7/9 =
    (3i3/6 - 2i4/6)^2 + 2/3 +7/9 =
    (2i9/6 - 2i4/6)^2 + 2/3 +7/9 =
     (5/6)^2 + 2/3 +7/9 =
     25/36 + 2/3 + 7/9 =
     25/36 + 24/36 + 28/36 = 77/36 = 2i5/36
b)
(2/3 + 1i1/2) : ( 4i1/2)^2 - 18 i1/6 =
(4/6 + 1i3/6) : (9/2)^2 - 18i1/6=
1i7/6 : 81/4 - 18i1/6=
13/6 * 4/81 - 18i1/6 =
13/3 * 2/81 - 18 i1/6=
26/243 - 18i1/6 =
52/486 - 18 i 81/486 = - 18 i 29/486