Question

6buah pipa berbentuk tabung dgn keliling 8phi hitunglah
A.jari jari pipa
B.panjangtali minimal utk mengikat pipa

Answer 1

Keliling = 2 x 3,14 x r
(8 x 3,14)/6 = 2 x 3,14 x r
8 x 3,14 = 2 x 3,14 x r x 6
8 x 3,14 = 12 x 3,14 x r
r = 8 x 3,14 / 12 x 3,14
r = 2/3

panjang tali minimal
= 12 x 2/3 + 2 x 3,14 x 2/3
= 8 + 4,19
= 12,19

Answer 2

Jawab: ↓

A.)Jari-jari pipa!

keliling = 2 × 3,14 × r

Keliling = (8 × 3,14)/6 = 2 × 3,14 × r

Keliling = 8 × 3,14 = 2 × 3,14 × r × 6

Keliling = 8 × 3,14 = 12 × 3,14 × r

Keliling r = 8 × 3,14 ÷ 12 × 3,14

Keliling r = ⅔.

B.)panjang tali minimal untuk meningkat pipa!

Panjang = (12 × ⅔) + (2 × 3,14 × ⅔)

Panjang = 8 + 4,19.

Panjang = 12,19 perbuah pipa.

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