Suma trzech liczb wynosi 35 2/3. Pierwsza z nich jest większa od drugiej o 5 1/3, a od trzeciej o 3 5/6. Znajdź te liczby. prosze i dziękuję.
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x - druga liczba
Mamy
x + 5 1/3 - pierwsza liczba
( x + 5 1/3) - 3 5/6 - trzecia liczba
zatem
[ x + 5 1/3 ] + x + [ x + 5 1/3 - 3 5/6] = 35 2/3
3x + 10 2/3 - 3 5/6 = 35 2/3
3x = 35 2/3 - 10 2/3 + 3 5/6
3x = 25 + 3 5/6
3x = 28 5/6 = 173/ 6
x = (173/6) : 3
x = 173/18 = 9 11/18 <--- druga liczba
==============
173/18 + 5 1/3 = 173/18 + 5 6/18 = 173/18 + 96/18 = 269/18 = 14 17/18
14 17/18 <- pierwsza liczba
===========
14 17/18 - 3 5/6 = 14 17/18 - 3 15/18 = 11 2/18
11 2/18 = 11 1/9 <--- trzecia liczba
===================
spr.
14 17/18 + 9 11/18 + 11 2/18 = 34 30/18 = 35 12/18 = 35 2/3
Odp. Te liczby, to:
14 17/18; 9 11/18 ; 11 2/18
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[ x + 5 1/3 ] + x + [ x + 5 1/3 - 3 5/6] = 35 2/3
3x + 10 2/3 - 3 5/6 = 35 2/3
3x = 35 2/3 - 10 2/3 + 3 5/6
3x = 25 + 3 5/6
3x = 28 5/6 = 173/ 6
x = (173/6) : 3
x = 173/18 = 9 11/18 - Druga liczba
173/18 + 5 1/3 = 173/18 + 5 6/18 = 173/18 + 96/18 = 269/18 = 14 17/18
14 17/18 - Pierwsza liczba
14 17/18 - 3 5/6 = 14 17/18 - 3 15/18 = 11 2/18
11 2/18 = 11 1/9 - Trzecia liczba
Te liczby, to:
14 17/18
9 11/18
11 2/18