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log3 1/9-log3 1/3=-2+1=-1
log1/2 1/2+log1/2 2=1-1=0
log1/3 9+log1/3 27=-2+(-3)=-5
log4 2+log1/4 1/8=½+⅔=7/6
log6 6pierwistków kwadratowych z 6-log1/6 36=3/2-2=-½
prosze o szybką odpowiedź. przy log-ach na