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grp = 500 gr
i = 1+ (n-1).α ( pakai i karena merupakan larutan elektrolit)
i=1+(2-1)1
i=2
kf air = 1,86
mr air = 18 gr/mol
dit : Tf =....?
peny :
ΔTf = Kf x m x i
=1,86 x (grt/mr x 1000/grp) x 2
=1,86 x (5,85/18 x 1000/500) x 2
= 1,86 x 0,325 x 4
=2,418 C
karena yg dit. adalah titik beku,
maka Tb = 0 - 2,418 C
Tb = - 2,418 C.
cat. kenapa harus dikurangi nol, karena air membeku pada suhu 0 derajat C.