y = 1/(x² + 4) y' = m = -2x /(x² + 4)² untuk x = 1 .→ m = (-2)/(1+4)² = (-2)/(5)² = -2/25
pers garis singgung m = -2/25 di titik (1 , 1/5) y = m( x - x1) + y1 y = - 2/25 ( x+ 1) + 1/5 ..} kali 25 25 y = -2 (x +1 ) + 5 25 y = -2 x + 3 2x - 25 y + 3 = 0
Verified answer
Jawaby = 1/(x² + 4)
y' = m = -2x /(x² + 4)²
untuk x = 1 .→ m = (-2)/(1+4)² = (-2)/(5)² = -2/25
pers garis singgung m = -2/25 di titik (1 , 1/5)
y = m( x - x1) + y1
y = - 2/25 ( x+ 1) + 1/5 ..} kali 25
25 y = -2 (x +1 ) + 5
25 y = -2 x + 3
2x - 25 y + 3 = 0