Question

Tentukan nilai x yg memenuhi persamaan berikut.
a. 2^6x-1 = 32
b. (1/3)^-2x+1 = 243
c. (1/5)^3x-1 = 25^-x+3

ket :
^ = pangkat

tolong dgn caranya ya.. mksh

Answer 1

A. 2^6x-1 = 32
    2^6x-1 = 2^5
    jadi 6x - 1 = 5
         6x      = 6
          x      = 1
b. (1/3)^-2x+1 = 243
(3^-1)^-2x+1 = 3^5
3^2x-1 = 3^5
 Jadi 2x-1 = 5       
 2x = 6       
X = 3

c. (1/5)^3x-1 = 25^-x+3
(5^-1)^3x-1 = (5^2)^-x+3
5^-3x+1 = 5^-2x-6
Jadi -3x+1 = -2x-6       
 -3x+2x  = -6 -1      
 -x     =  -7    
 X     =  7