tribeking22
2 sin^2 x - 7 sin x + 3 = 0 2 sin^2 x - 6 sin x - sin x + 3 = 0 2 sin x(sin x - 3) - 1(sin x - 3) = 0 (2 sin x - 1)(sin x - 3) = 0
2 sin x - 1 = 0 2 sin x = 1 sin x = 1/2 x = π/6, 5π/6
sin x - 3 = 0 sin x = 3 x = ∅
HP = {π/6, 5π/6}
Jawaban: B
1 votes Thanks 0
virgeenanuvi
2 sin^2 x - 7 sin x + 3 = 0 pada interval 0 < x < phi atau 0 < x < 180 misal sin x = x
2 x^2 - 7x + 3 = 0 (2x - 1)(x - 3) = 0 x = 1/2 atau x = 3 sin x = 1/2 atau sin x = 3 **dipakai yang sin x = 1/2**
sin x = 1/2 sin x = sin 30 x = 30 + k.360 atau x = (180 - 30) + k.360
(i) x = 30 + k.360 k = 0 >> x = 30 + 0.360 x = 30 k = 1 >> x = 30 + 1.360 x = 390 (tidak ada diinterval) (ii) x = (180 - 30) + k.360 x = 150 + k.360 k = 0 >> x = 150 + 0.360 x = 150 k = 1 >> x = 150 + 1.360 x = 510 (tidak ada diinterval)
2 sin^2 x - 6 sin x - sin x + 3 = 0
2 sin x(sin x - 3) - 1(sin x - 3) = 0
(2 sin x - 1)(sin x - 3) = 0
2 sin x - 1 = 0
2 sin x = 1
sin x = 1/2
x = π/6, 5π/6
sin x - 3 = 0
sin x = 3
x = ∅
HP = {π/6, 5π/6}
Jawaban: B
misal sin x = x
2 x^2 - 7x + 3 = 0
(2x - 1)(x - 3) = 0
x = 1/2 atau x = 3
sin x = 1/2 atau sin x = 3
**dipakai yang sin x = 1/2**
sin x = 1/2
sin x = sin 30
x = 30 + k.360 atau x = (180 - 30) + k.360
(i) x = 30 + k.360
k = 0 >> x = 30 + 0.360
x = 30
k = 1 >> x = 30 + 1.360
x = 390 (tidak ada diinterval)
(ii) x = (180 - 30) + k.360
x = 150 + k.360
k = 0 >> x = 150 + 0.360
x = 150
k = 1 >> x = 150 + 1.360
x = 510 (tidak ada diinterval)
HP = {30, 150)
HP = {phi/6, 5phi/6} (B)