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BD adalah diagonal segiempat ABCD
AD = 2 ; AB = 3
BC = x ; DC = 2BC = 2x
dari ΔABD
DB² = AB² + AD² - 2·AB·AD·cos 60°
DB² = 3² + 2² - 2·3·2·1/2
DB² = 9 + 4 - 6
DB² = 7
DB = √7
dari ΔBCD
DB² = BC² + CD² - 2·BC·CD·cos 60°
7 = x² + (2x)² - 2·x·2x·1/2
7 = x² + 4x² - 2x²
7 = 3x²
x² = 7/3
x = √(7/3) = 1/3 √21
x = BC = 1/3 √21
semoga membantu ^^