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syarat sejajar m1=m2
masukkan ke persamaan
(y-y1)=m(x-x1)
(y-(-1))= -4(x-(-2))
y+1=-4(x+2)
y+1=-4x-8
y=-4x-8-1
y=-4x-9
2))) 3x +3y+4=0
3y=-3x-4
y=-x-4/3
jd m1=-1
syarat tegak lurus m1 x m2 =-1
-1 x m2 =-1
m2 = 1
masukkan ke persamaan
(y-y1)=m(x-x1)
(y-3)=1(x-0)
y-3=x-0
y=x+3
3)) 6x-2y+3=0
m1=-a/b= -6/-2= 3
syarat sejajar m1=m2=3
(y-y1)=m(x-x1)
y-(-3)=3(x-1)
y+3=3x-3
y=3x-3-3
y=3x-6
jika kamu puas dengan jawaban ku beri jawaban terbaik ya