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p = 2s ec. 2
t-50 = s+50 ec. 3
de la ec. 3:
t = s+50+50 = s+100 ec. 4
Sustituyendo valores de la ec. 2 y 4 en la ec. 1:
p+s+t = 2500
2s + s + s+100 = 2500
4s + 100 = 2500
4s = 2500-100
4s = 2400
s = 2400/4
s = 600
De la ec. 2:
p = 2s
p = 2*600
p = 1200
De la ec. 4:
t = s+100
t = 600+100
t = 700
1200+ 600+700 = 2500 comprobado
Por tanto:
La primera tiene 1200 soles
La segunda 600 soles
La tercera 700 soles
Saludos.......