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Bab Program LinearMatematika SMA Kelas XI
4x + y ≥ 4
2x + 3y ≥ 6
4x + 3y ≤ 12
langkah awal, digambar
terjadi perpotongan 4x + y ≥ 4 dan 2x + 3y ≤ 6
4x + y = 4
y = 4 - 4x
2x+ 3y = 6
2x + 3(4 - 4x) = 6
2x + 12 - 12x = 6
-10x = 6 - 12
-10x = -6
x = -6/-10
x = 3/5
y = 4 - 4x
= 4 - 4 . 3/5
= 4 - 12/5
= (4 . 5 - 12)/5
= 8/5
titik potong = (3/5, 8/5)
titik uji = { (3/5, 8/5), (3, 0), (0,4) }
f(x, y) = x + y
f(3/5 + 8/5) = 3/5 + 8/5 = 11/5 = 2 1/5
f(3, 0) = 3 + 0 = 3
f(0, 4) = 0 + 4
maka, nilai minimum atau terkecil adalah 2 1/5
jawabannya B