Tolong bantu jawab yah... 1. hasil dari 2 sin 75° cos 75° 2. diketahui sin x = 5/13. nilai dari sin 2x adalah 3. jika sin x = 4/5. nilai tan 2x adalah
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3. sin x = y/r = 4/5 : x=3 cos x = x/r = 3/5 tan x= sin x /cos x = (4/5) / (3/5) = 4/3 tan 2x = (2 tan x)/(1-tan²x) = (2×4/3)/(1-(4/3)²) = (8/3) / (1-(16/9) = -24/7
2. sin x = y/r = 5/13 ; x=12 cos x = x/r = 12/13 sin 2x = 2 sinx cosx = 2×5/13×12/13 = 120/169
cos x = x/r = 3/5
tan x= sin x /cos x = (4/5) / (3/5) = 4/3
tan 2x = (2 tan x)/(1-tan²x)
= (2×4/3)/(1-(4/3)²)
= (8/3) / (1-(16/9)
= -24/7
2. sin x = y/r = 5/13 ; x=12
cos x = x/r = 12/13
sin 2x = 2 sinx cosx
= 2×5/13×12/13
= 120/169
1. 2sin75°cos75°=sin2×75
=sin150°
=1/2