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mCuSO₄*5H₂O=250u
mH₂O=250u-160u = 90u
%H₂O = (90/250)*100% = 36%
Masa: 63,5 + 32+4*16=159,5g
Hydrat soli ma wzór: CuSO4*5H2O
249,5g - masa całego hydratu
249,5g-100%
90g - x5 x=36%