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bola pejal
m R
v
kecepatan sudut
v = ω R
→ ω = v / R
momen inersia bola pejal
I = (2/5) m R²
Energi kinetik translasi
Ekt = ½ m v²
Energi kinetik rotasi
Ekr = ½ I ω²
Ekr = ½ • (2/5) m R² • (v / R)²
Ekr = (1/5) m v²
Perbandingan
Ekt : Ekr
= ½ m v² : (1/5) m v²
= 5 : 2 ← jwb