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P - pole
2x + 2y = 120 [cm]
y = (120-2x)/2 = 60 - x
P = xy = x(60-x) = -x² + 60x = -x(x-60)
a < 0 => wartość max dla x wierzchołka [xw]
xw = -b/2a = -60/-2 = 30
x = 30
y = 60 - x = 30
Będzie to kwadrat o boku 30.