Jumlah kelereng A terhadap kelereng B adalah 3/4.kelereng B terhadap C adalah 4/5. jumlah kelereng mereka bertiga 72 butir.hitung berapa banyak kelereng masing masing! Tolong buatin caranya ya,terima kasih.
keyne13
A : B = 3 : 4 B : C = 4 : 5 A : B : C = 3 : 4 : 5
kelereng A = x 72 = 18 kelereng B = x 72 = 24 kelereng C tinggal di kurangi aja, 72-18-24 = 30
anggunasm
A = 3/4 B B = 4/5 C B disubstitusikan ke A A = 3/4 × 4/5 C = 12/20 C = 3/5 C A + B + C = 72 3/5C + 4/5 C + 5/5 C = 72 12/5 C = 72 C = 72 × 5/12 = 30
A = 3/5 C = 3/5 × 30 = 18 B = 4/5 C = 4/5 × 30 = 24
B : C = 4 : 5
A : B : C = 3 : 4 : 5
kelereng A = x 72 = 18
kelereng B = x 72 = 24
kelereng C tinggal di kurangi aja, 72-18-24 = 30
B = 4/5 C
B disubstitusikan ke A
A = 3/4 × 4/5 C
= 12/20 C = 3/5 C
A + B + C = 72
3/5C + 4/5 C + 5/5 C = 72
12/5 C = 72
C = 72 × 5/12 = 30
A = 3/5 C = 3/5 × 30 = 18
B = 4/5 C = 4/5 × 30 = 24
NB : C = 5/5 karena 5/5 itu sendiri nilainya 1