Respuesta:
A = 2K[tex]m^{2}[/tex]
Explicación paso a paso:
Area de un rectangulo: A = base"b" x altura"h"
Datos:
b = 2/5 hm ; 1/2 hm
Hecto "h" = [tex]10^{2}[/tex]
Kilo "K" = [tex]10^{3}[/tex]
Solución:
A = [tex](\frac{2}{5} )(10^{2} )(\frac{1}{2} )(10^{2} )[/tex]
A = [tex](\frac{2}{5} )(2)(5)(10)(\frac{1}{2})(2)(5)(10)[/tex]
A = [tex](4)(10)(5)(10)\\[/tex]
A = (20)([tex]10^{2}[/tex])
A = 2(10)([tex]10^{2}[/tex])
A = 2([tex]10^{3}[/tex])[tex]m^{2}[/tex]
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Verified answer
Respuesta:
A = 2K[tex]m^{2}[/tex]
Explicación paso a paso:
Area de un rectangulo: A = base"b" x altura"h"
Datos:
b = 2/5 hm ; 1/2 hm
Hecto "h" = [tex]10^{2}[/tex]
Kilo "K" = [tex]10^{3}[/tex]
Solución:
A = [tex](\frac{2}{5} )(10^{2} )(\frac{1}{2} )(10^{2} )[/tex]
A = [tex](\frac{2}{5} )(2)(5)(10)(\frac{1}{2})(2)(5)(10)[/tex]
A = [tex](4)(10)(5)(10)\\[/tex]
A = (20)([tex]10^{2}[/tex])
A = 2(10)([tex]10^{2}[/tex])
A = 2([tex]10^{3}[/tex])[tex]m^{2}[/tex]
A = 2K[tex]m^{2}[/tex]