Question

5 gram urea CO(NH2)2 Mr =60 dilarutkan dalam 800 gram air. Tentukan molalitas larutan utea tersebut

Answer 1

Dik :
m = 5 gram
Mr = 60 gram/mol
m air = 800 gram
p air = 1 gram/cm³
Dit :
Q = ?
Jawab :
Q = n / V
Q = ( m/Mr ) / ( p air/m air )
Q = ( 5 / 60 ) / ( 1 / 800 )
Q = ( 1 / 12 ) / ( 1 / 800 )
Q = 66,6666667
Q = 66,67 M

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