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(2m+n)³=(2m)³+3(2m)²n+3(2m)n²+n³=8m³+12m²n+6mn²+n³
(∛7-1)³=(∛7)³-3(∛7)²(1)+3(∛7)(1)²-1³=6-3∛49+3∛7
(a-3)³=a³+3(a)²(3)+3(a)(3)²+3³=a³+9a²+27a+27