Question

Mohon bantuannya ya:)
Diketahui tan A = -2/5 (di kuadran II) Tentukan; Sin A, Cos A, Tan A

Answer 1

Dengan:
Kuadran II.
tan A = y/x
Sehingga,
y = 2
x = -5
r = √29 (Phytagoras)
Maka,
sin A = y/r = 2/√29 = 2/29 √29
cos A = x/r = -5/√29 = -5/29 √29
tan A = y/r = -2/5 (Ada pada soal)

Answer 2

Dengan
Kuadran II.
tan A = y/x

Maka :
y = 2
x = -5
r = √29

Maka,
sin A = y/r = 2/√29 = 2/29 √29
cos A = x/r = -5/√29 = -5/29 √29
tan A = y/r = -2/5

Semoga membantu