obwód podstawy graniastosłupa prawidłowego czworokatnego jest rowna 20 obietosc 30 oblicz pole powiezchni calkowitej
wyszlo mi ze h to 30/25=6/5 blagam wytlumaczcie
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4 a = 20
więc
a = 5
V = 30
ale
V = Pp*h = a^2 *h => h = V/ a^2 = 30 / 5^2 = 30/25 = 6/5
Pc = 2 Pp + Pb = 2 a^2 + 4a*h = 2 * 5^2 + 4*5* (6/5) = 50 + 24 = 74
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