(⅘)⁻⁷ * (5⁻⁵ : 4⁻⁶) =
bardzo bym prosil o rozwiazanie
(4/5)^-7 x (5^-5 : 4^-6) =(4/5)^-7 x 1/5^5 x 4^6 = 4^-7/5^-7 x 4^6/5^5 =
= 4^(-7 +6)/5 ^(-7 +5) = 4^-1/5^-2 =1/4 x 5^2 = 25/4 = 6 i1/4
(^ do potęgi)
(4/5)⁻⁷ *(5⁻⁵ : 4⁻⁶) = (5/4)⁷ *[1 /5⁵ : 1/4⁶] = 5⁷/4⁷ *4⁶/5⁵ = 5²/4 = 25/4 =6 ¹/₄
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(4/5)^-7 x (5^-5 : 4^-6) =(4/5)^-7 x 1/5^5 x 4^6 = 4^-7/5^-7 x 4^6/5^5 =
= 4^(-7 +6)/5 ^(-7 +5) = 4^-1/5^-2 =1/4 x 5^2 = 25/4 = 6 i1/4
(^ do potęgi)
(4/5)⁻⁷ *(5⁻⁵ : 4⁻⁶) = (5/4)⁷ *[1 /5⁵ : 1/4⁶] = 5⁷/4⁷ *4⁶/5⁵ = 5²/4 = 25/4 =6 ¹/₄
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