√5-√3(√5+√3)=
(√11+2)(√11-2)=
(√15-√6)(√5-√2)=
2(b-3c)(b+3c)=
√5-√3(√5+√3)=√5-√15+3
(√11+2)(√11-2)=11-2√11+2√11-4=7
(√15-√6)(√5-√2)=√75-√30-√30+√12=√25*3-2√30+√4*3=5√3-2√30+2√3=7√3+2√30
2(b-3c)(b+3c)=2(b²+3bc-3bc-9c²)=2b²-18c²
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√5-√3(√5+√3)=√5-√15+3
(√11+2)(√11-2)=11-2√11+2√11-4=7
(√15-√6)(√5-√2)=√75-√30-√30+√12=√25*3-2√30+√4*3=5√3-2√30+2√3=7√3+2√30
2(b-3c)(b+3c)=2(b²+3bc-3bc-9c²)=2b²-18c²