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x^3+y^3 = (x+y)^3 - 3xy(x+y)
49/4 = (1)^3 - 3xy(1)
49/4 = 1 - 3xy
3xy = 1 - 49/4
3xy = -45/4
xy = -45/12
xy = -15/4
masuk ke pertanyaan
x^2 + y^2 = (x+y)^2 - 2xy
= (1)^2 - 2(-15/4)
= 1 - (-7/4)
= 1 + 7/4
= 2 + 3/4
= 2,75
*CMIIW